How much tv do college students watch? a survey of 361 students recorded the number of hours of television they watched per week. the sample mean was 6.504 hours with a standard deviation of 5.584. the standard error of the mean was 0.294. find a 90% confidence interval for the population mean. round your answer to three decimal places

90% confidence interval would be (6.022,6.986).

Step-by-step explanation:

Since we have given that

Number of students = 361

Sample mean = 6.504

Sample standard deviation = 5.584

Standard error of the mean = 0.294

At 90% confidence level,

So, α = 0.01

So, z = 1.64

Margin of error is given by

So, Lower limit would be

Upper limit would be

So, 90% confidence interval would be (6.022,6.986).

47 - 90 = 43

43 - 180 = x

x = 137