Acar is traveling at 98 km/h when the driver sees an accident 85 m ahead and slams on the brakes. what minimum constant deceleration is required to stop the car in time to avoid a pileup?

-56494.12km/h2

Step-by-step explanation:

We use one of the equations of motion to answer this question, preferably for one that has all the parameters we've been given

v2-u2=2as

v=final speed = 0

u=initial speed = 85km/h

s=distance = 85m =0.085km

a=acceleration

Then we make a the subject of formula

a=(v2-u2)/2s

Inputting all our values

a = -56494.12km/h2

the negative sign shows that it's decelerating

So therefore

deceleration = 56494km/h2

The workings is in the picture I sent

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

answer: can you give the

step-by-step explanation: