Take the laplace transform of the following initial value problem and solve for y(s)=l{y(t)}: y′′−2y′−24y=s(t)y(0)=0,y′(0)=0where s is a periodic function defined bys(t)={1,0,0≤t< 11≤t< 2, and s(t+2)=s(t) for all t≥0.hint: : use the formula for the laplace transform of a periodic function.

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

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step-by-step explanation:

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because parallelagram have all 4 angels the same size dependeing and a rectangle and square are oth parallelogram