The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. the distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4. using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 43 and 55?

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean

95% of all values lie within the 1 standard deviation from mean  

99.7% of all values lie within the 1 standard deviation from mean  

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

68% of all values lie within the 1 standard deviation from mean = =

95% of all values lie within the 2 standard deviation from mean  = =

99.7% of all values lie within the 3 standard deviation from mean  = =

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

step-by-step explanation:

mathpapa

step-by-step explanation: