Jim is designing a seesaw for a children's park. the seesaw should make an angle of 45° with the ground, and the maximum height to which it should rise is 1 meter, as shown below: a see-saw is shown with one end on the ground and the other in the air. the see-saw makes an angle of 45 degrees with the groun what is the maximum length of the seesaw? (6 points) 1 meter 1.4 meters 2 meters 0.5 meters

The maximum length is 1.4 meters.

Step-by-step explanation:

The seesaw forms a triangle as shown in the figure, whose hypotenuse is the length of seesaw. Thus from trigonometry:

Which is the maximum length of the seesaw that we need if it is to rise to 1 meters above the ground.

30

step-by-step explanation:

times by times

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°