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find the number of real number solutions for the equation. x2 + 5x + 7 = 0
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Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

The number of real solutions for the equation is zero

Solution:

For a Quadratic Equation of form :  ---- eqn 1

The solution is  

Now , the given Quadratic Equation is  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In , is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

46 dollars is the answer.

step-by-step explanation:

6*6 = 36,         36+10=46