Y+ 7 = - 2/5 * (x - 10) . what is thethe point-slope of the equation of the line that passes through (- 5, - 1) and (10, - 7) is standard form of the equation for this line? 2x - 5y = - 15 2x - 5y = - 17 2x + 5y = - 15 2x + 5y = - 17

The Standard Form of the Equation is A. 2x - 5y = -15

Step-by-step explanation:

Given points: (-5, -1) and (10, -7).

Find the slope:

m = (y - y1)/(x - x1)

= -1 - (-7)/-5 - 10

= -1 + 7/-15

= 6/-15

m = -2/5

You already had the point slope form:

y - y1 = m(x - x1)

y - (-7) = -2/5(x - 10)

y + 7 = -2/5(x - 10)

The rest of the question is looking for the standard form of the equation:

Ax + By = C

Begin by solving the point slope form for y:

y + 7 = -2/5x + 20/5

y + 7 = -2/5x + 4

y = -2/5x - 3

Now, put the equation into the standard form:

y + 2/5x = -3

Multiply by 5, and place x first:

2x + 5y = -15, the Standard form of the Equation

Prove by setting x = 0 and finding the y intercept:

5y + 2(0) = -15

5y = -15

y = -3, giving the y intercept, when x = 0 as -3 or (0, -3)

Hope this helps  :-)

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4