Atriangle drawn on a map has sides sides of lengths 9.0 cm, 12 cm, and 14 cm. the shortest of the corresponding real-life distance is 94 km. find the longest of the real-life distances. round to the nearest unit.

Approximately 146 km

Step-by-step explanation:

The triangle drawn on the map is drawn to a certain scale. The triangle on the map is similar to the triangle in real life. This means that the distances on the map corresponds to the distances in the real life .

Ratio of the distance of the longest side on the map to the distance of the longest side in real life = ratio of the distance of the shortest side on the map to the distance of the shortest side in real life = ratio of the distance of the third side on the map to the distance of the third side in real life.

The shortest side on the map is 9cm

The longest side on the map is 14cm

Let the longest side in real life be x km

Therefore,

9/94 = 14/x

9x = 94 × 14 = 1316

x = 1316/9 = 146.22 km

Approximately 146 km

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

the answer will be the last one