First answer will mark brainliest, all answers will receive 5 stars!

at time t=0, a ball is thrown downward at 24 feet per second from a height of 160 feet above the ground. the equation h = -16t^2 - 24t +160 describes the height (in feet) of the ball. in how many seconds will the ball hit the ground?

After 2.5 seconds.

Step-by-step explanation:

The function represents the height of the ball. So when it hits the ground, the height of the ball is 0. You set h = 0 and solve for t. Once you do that, you get t = -4, 2.5. However, time can't be negative so only 2.5 seconds is an answer

by asker of question~

Step-by-step explanation:

this response is just to mark the frst person brainliest cos i promised :D

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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0,0

step-by-step explanation: