Which graph represents a quadratic function with a vertex at (0, 0)? on a coordinate plane, a parabola opens up. it goes through (negative 5, 6), has a vertex of (0, 1), and goes through (5, 6). on a coordinate plane, a parabola opens up. it goes through (negative 6, 6), has a vertex of (0, negative 1), and goes through (6, 6). on a coordinate plane, a parabola opens up. it goes through (negative 5, 6), has a vertex of (0, 0), and goes through (5, 6). on a coordinate plane, a parabola opens up. it goes through (negative 2.5, 6), has a vertex of (3, 0), and goes through (7.5, 4).

  On a coordinate plane, a parabola opens up. It goes through (negative 5, 6), has a vertex of (0, 0), and goes through (5, 6).

Step-by-step explanation:

Since you want a graph with a vertex of (0, 0), choose the one that is described as having a vertex of (0, 0).

Option C.

Step-by-step explanation:

We need to find the graph which represents a quadratic function with vertex at (0,0).

The graph of quadratic function is a parabola (either upward or downward) and the extreme point of the parabola is know as vertex.

All graphs represent different parabolas.

Vertex of first parabola = (0,1)

Vertex of second parabola = (0,-1)

Vertex of third parabola = (0,0)

Vertex of fourth parabola = (3,0)

In option C, a parabola opens up on a coordinate plane. It goes through (-5, 6), has a vertex of (0, 0), and goes through (5, 6).

Only third graph represents a quadratic function with a vertex at (0, 0).

Therefore, the correct option is C.

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)

um is there supposed to be a picture?