Mike was selling raffle tickets for the school football game. the raffle tickets were $3 for students and $7 for adults. when mike looked at how much he collected, he counted $455 and 101 ticket stubs. how many student and adult tickets were sold?

63 student tickets and 38 adult tickets were sold

Step-by-step explanation:

Mike sold raffle tickets for adults and students for the school football game.

Let x= number of student tickets sold

Let y= number of adult tickets sold

The raffle tickets were $3 for students and $7 for adults. This means x student tickets cost $3x and y adult tickets cost $7y

When Mike looked at how much he collected, he counted $455 and 101 ticket stubs. This means

3x + 7y = 455 - - - - - -1

x + y = 101

Substituting x = 101 - y into equation 1, it becomes

3(101 - y) + 7y = 455

303 -3y + 7y = 455

-3y +7y = 455 - 303

4y = 152

y = 152/4 = 38 tickets

x = 101 - y

x = 101 - 38

x = 63 tickets

b

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!