Aprivate plane traveled from seattle to a rugged wilderness, at an average speed of 312312 mph. on the return trip, the average speed was 364364 mph. if the total traveling time was 44 hours, how far is seattle from the wilderness?

Distance from Seattle to wilderness = 7392 miles.

Step-by-step explanation:

A private plane traveled from Seattle to a rugged wilderness, at an average speed of 312 mph. On the return trip, the average speed was 364 mph.

   Total travel time = 44 hours

Let the distance from Seattle to wilderness be s.

We have

Distance from Seattle to wilderness = 7392 miles.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72