express y – 5x = 5 in standard form.

The standard form of y - 5x = 5 is 5x – y = -5

Solution:

Given equation is y - 5x = 5

We have to express in standard form

The standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers.

The standard form of a line is just another way of writing the equation of a line.

So, to write the given equation in standard form we need to rearrange the terms.

Hence the equation becomes:

y - 5x = 5

On rearranging the terms, we get

-5x + y = 5

We need the x-term to be positive, so multiply the equation by -1 to get our answer

5x - y = -5

Hence the standard form is found out

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

The linear equation is: y=ax+b