Two pipes are connected to the same tank. when working together, they can fill in 2hrs. the larger pipe, working alone, can fill the tank in 3 hrs less time than the smaller one. how long would the smaller one take, working alone, to fill the tank?

The smaller pipe can fill the tank in 6 hours alone.

Step-by-step explanation:

Let us assume that the smaller pipe can fill the tank alone in x hours and the larger pipe fills it in (x - 3) hours.

Therefore, the smaller pipe in 1 hour can fill part of the tank.

Again the larger pipe in 1 hour can fill part of the tank.

So, if both the pipes are open then, in 1 hour they can fill ( part of the tank.

Therefore, they can fill the full tank in hours.

As per given condition, we can write

⇒ x² - 3x = 4x - 6

⇒ x² - 7x + 6 = 0

⇒ (x - 6)(x - 1) = 0

⇒x = 6 or x = 1

But x can not be less than 2 hours.

So, x = 6 hours.

Therefore, the smaller pipe can fill the tank in 6 hours alone. (Answer)

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.