In a survey of 100 out-patients who reported at a hospital on a day, it was found that 70 complained of fever, 50 had stomach troubles and 30 were injured. the entire 100 patients had one or more of the complaints, 44 had exactly two of them.
how many patients had all the three complaints?

3 patients had all the three complaints

Step-by-step explanation:

Let U be the set of patients who reported at the hospital on that day

Let F be the set of patients who complained of fever

Let S be the set of patients who had stomach troubles

Let I be the set of injured patients

Then the given data can be written as:

n(F∩S∩I) = ?

Using the formula for the cardinal number of union of three sets:

n(F∪S∪I) = n(F) + n(S) + n(I) - n(F∩S) - n(S∩I) - n(I∩F) + n(F∩S∩I)

100 = 70 + 50 + 30 - (44 + 3×n(F∩S∩I)) + n(F∩S∩I)

100 = 150 - 44 - 2×n(F∩S∩I)

2×n(F∩S∩I) = 106 - 100 = 6

n(F∩S∩I) = 3

show us the picture

step-by-step explanation:

show the !

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)