Carlos pays a monthly fee of $12, and he pays an additional $0.05 per minute. the least he has been charged in a month is $85.15. what are the possible # of minutes he has used his phone in a month? use m for the number of minutes, and solve your inequality for m.

The number of possible minutes M is greater than 1462.4.

Step-by-step explanation:

The monthly fee of the call charges  = $12

Cost per minute = $0.05

Least amount bill charged to Carlos = $85.15

Let us assume the the number of minutes used on the phone  = M

So, the cost of M minutes = m (Cost of 1 minute)

                                           = M x ( $0.05) =  0.05 M

Total Bill Charges  <  Fixed Fee + Cost of M minutes

⇒$85.15  <  $12 + 0.05 M

or, 85.15 < 12 + 0.05 M

or, 0.05 M < 85 .15 - 12 = 73.12

⇒ M  < 73.12 / 0.05 = 1462.4

or M  =  1462.4

Hence, the number of possible minutes M >   1462.4

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: