In fall 2014, 34% of applicants with a math sat of 700 or more were admitted by a certain university, while 16% with a math sat of less than 700 were admitted. further, 38% of all applicants had a math sat score of 700 or more. what percentage of admitted applicants had a math sat of 700 or more? (round your answer to the nearest percentage point.)

Our required percentage would be 57%.

Step-by-step explanation:

Since we have given that

Probability of applicants with a Math SAT of 700 or more were admitted = 34%= P(A|E)= 0.34

Probability of applicants with a Math SAT of less than 700 were admitted = 16% = 0.16 = P(A|E')

Probability of all applicants had a Math SAT score of 700 or more = 38% = 0.38=P(E)

Probability of all applicants had a Math SAT score of less than 700 = 100-38=62% = 0.62=P(E')

So, using Bayes theorem, we get that

Probability of admitted applicants had a Math SAT of 700 or more P(E|A)  is given by

Hence, our required percentage would be 57%.

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: