Alake has a native population of 1,000 frogs. the native frog population increases at a rate of 200 frogs per year. a new species of 10 frogs migrates to the lake. this new species’ population increases at a rate of 50% per year. when will the two populations equal each other? select to reveal each frog population’s growth model.

a system of equations can be created with the two functions to determine when the populations will have the same population output value, y.
y = 200x + 1,000
y = 10(1.5x)

to determine when the populations will be equal, set the equations equal to each other, and solve for x.
200x + 1,000 = 10(1.5x)

this equation is a little more challenging to solve by algebraic methods. in this lesson, you will solve systems of equations like the one above approximately by effectively using technology and tables.

1. Alright lets start off with the key points for example:

-native population of frogs is 1000

-200 new frogs per year of native frogs

-10 new frogs migrate to the lake

-50% more new frogs of the current population

So what I did was make a graph of the 2 equations for example:

y = 200x + 1000

y = 1.5^x · 10

Then you put them together to make 1 equation which is:

200x + 1000 = 1.5^x · 10

Which gives us the answer of 14.745 or rounded up to 15.

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.