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Mathematics, 21.11.2019 21:31 angelesramos112

The null and alternate hypotheses are:

h0 : μd ≤ 0

h1 : μd > 0

the following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

day
1 2 3 4
day shift 10 12 15 18
afternoon shift 8 9 13 17
at the 0.050 significance level, can we conclude there are more defects produced on the day shift? hint: for the calculations, assume the day shift as the first sample.
state the decision rule. (round your answer to 2 decimal places.)
compute the value of the test statistic. (round your answer to 3 decimal places.)
what is the p-value?
between 0.005 and 0.01
between 0.001 and 0.005
between 0.01 and 0.025
what is your decision regarding h0?
reject h0
do not reject h0

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The null and alternate hypotheses are:

h0 : μd ≤ 0

h1 : μd > 0
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