(2 points) an article in the washington post on march 16, 1993 stated that nearly 45 percent of all americans have brown eyes. a random sample of n=76n=76 americans found 28 with brown eyes. we test h0: p=.45 ha: p≠.45

(a) what is the z-statistic for this test?

(b) what is the p-value of the test?

a) z=1.43

b) 0.1528

Step-by-step explanation:

The given set of hypothesis :

Since the alternative hypothesis is two-tailed , so we perform two-tailed test.

Also, it is given that : A random sample of n=76 Americans found 28 with brown eyes.

Sample proportion:

a) The z-statistic would be :-

b) P-value for two-tailed test = 2P(Z>|z|)= 2P(z>|-1.43|)

=2P(z>1.43)

=2(1-P(z≤1.43)

=2-2P(z≤1.43)

= 2-2(0.9236)[Using standard z-table]

= 2-1.8472=0.1528

Hence,  the P-value of the test= 0.1528

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

step-by-step explanation:

3024 rhe base is what up in worry about