If the length of the rectangle is twice the width, and the perimeter of the rectangle is 30m, what is length and width of the rectangle

The length of the rectangle=10 m

The width of the rectangle=5 m

Step-by-step explanation:

Step 1: Determine the dimensions of the rectangle

let the width of the rectangle be;

width=w

length=2×w=2 w

Step 2: Determine the perimeter of the rectangle

P=2(L+W)

where;

P=perimeter of the rectangle

L=length of the rectangle

W=width of the rectangle

In our case;

P=30 m

L=2 w

W=w

replacing;

2(2 w+w)=30

4 w+2 w=30

6 w=30

w=30/6=5

w=5 m

The length of the rectangle=5×2=10 m

The width of the rectangle=5 m

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.