Aprobability density function is given by:

2 2 2 for 0

( )

0 otherwise,

h v av e v

f v

    



find:

(a) the expectation, [6]

(b) the variance

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

the answer to your question is b.

the answer is: -22 also a

hope i

-lavira: )