The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of .2 inches.

what is the probability that a randomly selected sample of 4 sheets will have an average length of less than 29.9 inches long?

 0.0668

Step-by-step explanation:

Given : The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

i.e. and

Let x denotes the lengths of aluminum-coated steel sheets.

Then the probability that a randomly selected sample of 4 sheets will have an average length of less than 29.9 inches long will be :-

  [by using the z-value table ]

Hence, the required probability = 0.0668

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

thus, the first answer choice, y = sec x, is the correct one