Solve the system of equations by substitution and show work.
y=−6x+13
y=3x+4

x= 1 , y = 7

Step-by-step explanation:

y = -6x + 13 equation 1

y = 3x + 4 equation 2

substitute y = 3x + 4 into equation 1 , then we have

3x + 4 = - 6x + 13

collect the like terms , we have

3x + 6x = 13 - 4

9x = 9

x = 1

substitute x = 1 into equation 2 , we have

y = 3(1) + 4

y = 3 + 4

y = 7

Therefore : x = 1 and y = 7

(1, 7 )

Step-by-step explanation:

Given the 2 equations

y = - 6x + 13 → (1)

y = 3x + 4 → (2)

Substitute y = 3x + 4 into (1)

3x + 4 = - 6x + 13 ( add 6x to both sides )

9x + 4 = 13 ( subtract 4 from both sides )

9x = 9 ( divide both sides by 9)

x = 1

Substitute x = 1 into (2) for corresponding value of y

y = 3(1) + 4 = 3 + 4 = 7

Solution is (1, 7 )

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

a is the right answer