Third-degree, with zeros of -3,-1 and 2, and passes through the point (4,7)

Step-by-step explanation:

       Assuming that the question is to find a third degree expression that has zeros and the equation passes through ,

       If the roots/zeroes of a order expression are given as , the expression is given by .

       Since we know the three roots of the third degree expression, the function is

       Also, passes through , so

∴Required expression is

step-by-step explanation:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐