Sin^2 (x)= 3/4 solve the equation for 0

x= π/3,  2π/3, 4π/3,  5π/3

Step-by-step explanation:

Sin^2 (x) = 3/4

Or, Sin^2 (x) - 3/4= 0

Or, Sin^ (x) - ( root 3/ 2)^ 2 = 0 ( Transformed 3/4 into √3/2 format so that if we square it, the value doesn't change)

Or, (Sin (x) + √3/2) (Sin (x) - √3/2) = 0

Or, Sin (x) =  ± (√3/2)

Hence, x= π/3, 2π/3, 4π/3,  5π/3 as the range is between 0 to 360 degree.

answer: r there any options?

step-by-step explanation: