Each of the digits 7, 5, 8, 9, and 4 is used only once to form a three-digit integer and a two-digit integer. if the sum of the integers is 555, how many such pairs of integers can be formed?

4 such pairs of integers can be formed.

Step-by-step explanation:

Consider the provided information.

Let the first number is "abc" and the second number is "de".

The sum should be 555.

Let us first find the unit digit of "abc" and "de".

The sum of 8 and 7 end up with 5.

So the number of possible ways are:

ab8+d7 Or ab7+d8

Now we are left with only 3 digits 4, 5 and 9.

The first digit must be 4.

Now the number will look like "4b8+d7" Or "4b7+d8"

b and d can be 5 and 9 or vise-versa.

Now the possible number are: (498, 57), (458, 97), (497, 58) and (457, 98)

Therefore, 4 such pairs of integers can be formed.

b) the dogs need to shift their focus to human scent.

answer: 3 x 2 = 6 and 6+0

step-by-step explanation: sum equals addition and twice is multiplication so its

3 x 2 = 6

6+0= 6

identity property of zero