Suppose that an outbreak of cholera follows severe flooding in an isolated town of 2500 people. initially (day 0), 30 people are infected. every day after, 18% of those still healthy fall ill. by what day will at least 87% of the population be infected?

On 11th day ( approx )

Step-by-step explanation:

Since, if a population change with a constant rate,

Then final population,

Where,

P = initial population,

r = rate of change per period,

t = number of periods,

Given,

Initial population = 2500,

Out of which, infected population = 30,

So, healthy people, initially = 2500 - 30 = 2470

Every day after, 18% of those still healthy fall ill.

So, after x days the number of healthy people,

Now, if 87% of 2470 are ill,

Then reaming healthy population = (100 - 87)% of 2470

= 13% of 2470

= 321.10

If P = 321.10,

From equation (1),

Hence, by 11 day at least 87% of the population be infected.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: