Solve using quadratic formula
5x^2-4x+3=0

Impossible

Step-by-step explanation:

In 5x^2-4x+3=0, standard form, substitute these values in the quadratic formula:

a = 5; b = -4; c = 3

The quadratic formula is

(ignore the weird capital A)

Substitute a b and c:

Simplify:

Because is the square root of a negative number, the answer would be imaginary.

Therefore, there are not solutions to this equation.

A solution is the same as the roots or zeroes, where the graph would cross the x-axis when graphed.

The graph never meets the x-axis. It looks like this:

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

what