£940 is divided between gavin, jim & krutika so that gavin gets twice as much as jim, and jim gets three times as much as krutika. how much does jim get

$282

Step-by-step explanation:

We can think of it as an equation system. Lets find out the equations.

There are 3 people: Krutika, Gavin and Jim. Lets call k Kutrika's money and g and j Gavin's and Jim's money respectively.

So, as Gavin gains twice as Jim we can say that:

g = 2j

Then, as Jim gets 3 times more than Kutrika:

j = 3k

And, as the whole sum is 940:

k + j + g = 940.

Notice that both Kutrika's and Gavin's money have a relation to Jim's money, so we can try to write them as function of Jim's money.

If we part from j = 3k and divide both sides by 3:

j/3 = k

So, using this last equation and g = 2j, replacing in the equation that sums the money of everyone:

k + j + g = 940

j/3 + j + 2j = 940

Putting together all the terms that have j imply using 3 as common denominator:

j/3 + 3j/3 + 6j/3 = 940

10j/3 = 940

Dividing both sides by 10/3 (or multiplying by 3/10):

j = 940/ (10/3) = 282

So, Jim has $282. Now we can use the relations we defined to find k and g:

k = j/3 =$94

g = 2j = $564

4x and 6y

im not sure though

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.