Where is the hole for the following function located?
f (x) = startfraction x + 3 over (x minus 4) (x + 3) endfraction
answer choices ->

x = –3
y = –3
x = 3
y = 3

At x = -3 is located a hole.

In this problem, we have the following function:

A hole will lie at the x-values that makes the function undefined, that is, when the denominator is zero. In a mathematical language:

From this equation, we get two solutions:

At those x-values the function will have a hole. From the choices:

At x = -3 is located a hole.

Derivative:

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step-by-step explanation: