Arectangle a small pool is 8 feet deep one side of the pool is 4.5 times longer than the other. the amount of what i needed for the swimming pool is 3600 ft.³ find the dimensions of the pool

The dimension of swimming pool is 45 feet by 10 feet by 8 feet .

Step-by-step explanation:

Given as :

The depth of pool = 8 feet

The one side of pool is 4.5 times longer than the other

Let the measure of other side = x feet

So, the measure of one side = 4.5 x

The volume of pool = 3600 ft³

Now, Volume of pool = Length×Breadth×Height

or, 3600 = x × 4.5 x × 8

Or, 4.5 x² =

or, 4.5 x² = 450

Or, x² =

Or,  x² = 100

∴ x = √100 = 10 feet

so,The measure of other side 10 feet , measure of one side =4.5 ×10 = 45 feet

Hence The dimension of swimming pool is 45 feet by 10 feet by 8 feet . Answer

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

agree

step-by-step explanation: