The chess club has 16 members and gains a new member every month. the film club has four members and gains four new members every month. write and solve a system of equations to find when the member members in both clubs will be equal

 16 + x  = 4 + 4x  is the required equation representing the situation.

After 4 months both the clubs will have SAME NUMBER of members.

Step-by-step explanation:

Let us assume in x months, both clubs will have same number of members.

The present members in chess club =  16

Gains a new member every month.

So, the members gained in  x months = x  (1)  = x

So, the Total members in Chess Club after x months

= Previous Members  + Addition in  x months   = 16 +x

The present members in Film club = 4

Gains a 4 member every month.

So, the members gained in  x months = x  (4)  = 4x

So, the Total members in Film Club after x months

= Previous Members  + Addition in  x months   =  4 +  4x

Now, according to question:

After x months both clubs have same members.

⇒  16 + x  = 4 + 4x

or, 16 - 4 = 4x- x

or, 3 x  = 12

⇒ x = 12/ 3  = 4 , or x  = 4

Hence, after 4 months both the clubs will have SAME NUMBER of members.

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step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.