The intensity of a sound varies inversely with the square of its distance from the source. at a distance of 1 meter, the intensity of a jet engine noise is 10 watts per square meter. an airport cargo worker is 15 meters from the jet engine. what is the sound intensity at this distance?

The sound intensity at the distance of 15 meters is 0.044 watts.

Step-by-step explanation:

Given as :

For the distance of 1 meter , the intensity of jet engine noise = 10 watts

∵ The intensity of sound is define as the power carried by sound waves per unit area in the direction perpendicular to that area

So , the intensity of sound is inversely proportional with square of distance

I.e     , where d is the distance

or,

Now ,

∵ For 1 meter the intensity of sound is 10 watts

∴  Let for 15 meter the intensity of sound is  

So ,

Or,

Or,   = × 10  watts

∴     = 0.044  watts

Hence The sound intensity at the distance of 15 meters is 0.044 watts. Answer

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

4a. is 3 miles every hour

4b. is 1/3 of an hour per mile

step-by-step explanation: