If i add the square of a number
to the number itself, i get 30.
what could the number be?

I know you could easily solve this just looking at it.

But if you want the algebraic solution:

x + x^2 = 30

x^2 + x -30 = 0

a = 1  

b = 1

c = -30

Using the quadratic formula:

x = [ -b +- sqr root (b^2 - 4ac) ] / 2a

x = [-1 +- sqr root (1 - 4 * 1 -30) ] / 2*1

x = [-1 +- sqr root (1 + 120) ] / 2

x = -1 +- sqr root (121) / 2

x1 = (-1 + 11) / 2 = 10 / 2 = 5

x2 = (-1 -11) / 2 = -12 / 2 = -6

Answers are 5 and -6

5 + 5^2 = 30

-6 + (-6)^2  = 30

-6 +36  = 30

Step-by-step explanation:

If I add the square of a number  to the number itself, I get 30, then the number can be 5 or -6

Solution:

Given that if i add the square of a number  to the number itself, I get 30

We have to find the number

Let the number be "x"

Square of number + number = 30

Hence we get,

Let us factorize the expression to get the value of "x"

"x" can be written as "-5x + 6x"

Now "30" can be written as

Take "x" as common from first two terms and "6" as common from next two terms

Equating to zero we get,

x - 5 = 0 or x + 6 = 0

x = 5 or x = -6

Hence the number can be 5 or -6

answer: i think one of the answer is $150 and $300?

step-by-step explanation:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.