2. george estimates that each bale of hay in his field weighs 62.5 pounds on
average. there are 892 bales to be picked up. if his truck can carry 8 tons on
one trip, how many trips will he have to make to move his bales?

4 trips

Step-by-step explanation:

there are 892 bales of hay

each one weighs about 62.5 pounds

892 * 62.5 = 55,750

George's truck can only carry 8 tons

1 ton = 2,000 pounds

2,000 * 8 = 16,000 pounds

So,

55,750 / 16,000 = 3.484375

But since you can't make 3.484375 trips in a truck, round it up.

3.484375 rounded up equals 4

George has to take 4 trips

there is no question content here, but you for the free points! : d

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;