You have 20 coins in your coin dish: 4 nickels, 3 dimes, 7 quarters, and 6 pennies. you draw one coin at random, do not replace it, then draw a second coin. find each probability:

a. you end up with 6 cents
b. you end up with 35 cents
c. you end up with 20 cents

Step-by-step explanation:

a. To get 6 cents, one coin needs to be a nickel and the other coin needs to be a penny.

P = P(nickel then penny) + P(penny then nickel)

P = (4/20) (6/19) + (6/20) (4/19)

P = 12/95

b. To get 35 cents, one coin needs to be a dime and the other coin needs to be a quarter.

P = P(dime then quarter) + P(quarter then dime)

P = (3/20) (7/19) + (7/20) (3/19)

P = 21/190

c. To get 20 cents, both coins need to be dimes.

P = P(dime then dime)

P = (3/20) (2/19)

P = 3/190

54

step-by-step explanation:

6x9

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺