Equation through (-1,4) and perpendicular to 3y=2x-1

The equation of line perpendicular to given line and passes through points  ( - 1 , 4 ) is 2y = -3x + 5

Step-by-step explanation:

Given line equation as :

3 y = 2 x - 1

Or, y = x -  

So ,  The equation is in the form of y = m x + c

Where m is the slope of the line

∴ satisfying the condition

Slope of given line is  m =

Now , ∵ The other line is perpendicular to this line and passes through point    ( - 1 , 4 )

Let , Slope of other line  = M  

∴ for perpendicular line condition , products of the slope = - 1

I.e m × M = - 1

Or , M = -

Or   M = -

Or   M =  -

Thus The equation of line with slope M and passing through points  ( - 1 , 4 ) is

or,   (x + 1)" alt="\frac{3}{2}" />   (x + 1)" />

or, 2y - 8 = - 3 (x +1)

Or, 2y - 8 = - 3x - 3

or   2y = - 3x - 3 + 8

∴   2y = -3x + 5

Hence The equation of line perpendicular to given line and passes through points  ( - 1 , 4 ) is 2y = -3x + 5  Answer

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

what? ?

what type of question is thiss

step-by-step explanation: