Which is the graph of f(x) = (2)-x ?
on a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. it crosses the y-axis at (0, 1).

on a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. it crosses the y-axis at (0, 1).

on a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. it crosses the y-axis at (0, 2).

We will choose option 2.

Step-by-step explanation:

The given function is

So, from the above equation it is clear that as x increases in the first quadrant the value of f(x) tends to zero and increases into second quadrant.{ Since x is negative in the second quadrant}

Again, for x = 0, y becomes 1, i.e. the function crosses the y axis at (0,1).

Therefore, on a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. (0, 1) point is the point of intersection with the y-axis.  

So, we will choose option 2. (Answer)

answer: 88

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.