You are selling candy and wrapping paper for the band's christmas fundraiser. the candy sells for 8 dollars per box and the wrapping paper sells for 6 dollars per roll. if you have sold 14 items, and collected 92 dollars, how many of each have you sold?

The number of boxes of candy sold is 4

The number of rolls of wrapping paper sold is 10

Step-by-step explanation:

Let x = number of boxes of candy that was sold.

Let y = number of rolls of wrapping paper was sold.

The candy sells for 8 dollars per box and the wrapping paper sells for 6 dollars per roll. This means that x boxes of candy and y rolls of wrapping paper will be sold for

$(8x + 6y)

If you have sold 14 items, and collected 92 dollars, this means that

x + y = 14

8x + 6y = 92 - - - - - - -1

Substituting x = 14 - y into equation 1, it becomes

8(14-y) + 6y = 92

112 - 8y + 6y = 92

- 8y + 6y = 92 - 112

-2y = -20

y = 20/2 = 10

x = 14 - y

x = 14 - 10

x = 4

The number of boxes of candy sold is 4.

The number of rolls of wrapping paper sold is 10.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

idk

step-by-step explanation: