7.
+ -10.27 points
bbunderstat12 6.1.007.
assuming that the heights of college women are normally distributed with mean 68 inches and standard deviation 1.9 inches, answer the following questions. (hint: use the figure below with
mean y and standard deviation o.)
area under a normal curve
2.35%/13.5%
34%
34%
13.5%
2.35%
- 30
-20
o
-
to
4 + 20
u + 30
u
68%
95%
99.79.
(a) what percentage of women are taller than 68 inches?
%
(b) what percentage of women are shorter than 68 inches?
%
(c) what percentage of women are between 66.1 inches and 69.9 inches?
0%
(d) what percentage of women are between 64.2 and 71.8 inches?

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

180°

step-by-step explanation:

sum of equilateral triangle=180°

< n=60°

< m=120°°[angle supplementary of equilateral angle]

< m+< r+< x=360°(sum of exterior angle of triangle)