Alocal tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. to support this claim, the customer asked the pro shop to string 17 new rackets at 59 psi. upon receiving the rackets, the customer measured the tension of each and calculated the following summary statistics: sample mean = 56, standard deviation = 2.4 psi. in order to conduct the test the customer selected a significance level of a = .05. interpret this value.

a. the probability of concluding that the true mean is less than 59 psi when in fact it is equal to 59 psi is only .05.

b. the probability of concluding that the true mean is less than 59 psi when in fact it is equal to 59 psi is only .05.

c. the smallest value of ? that you can use and still reject h0 is 0 .05.

d. there is a 5% chance that the sample will be biased

Step-by-step explanation:

Given that a  local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. To support this claim, the customer asked the pro shop to string 17 new rackets at 59 PSI. Upon receiving the rackets, the customer measured the tension of each and calculated the following summary statistics: sample mean = 56, standard deviation = 2.4 PSI.

Whenever we select alpha as 5% = 0.05 this means that whenever p value got from hypothesis test is less than this we reject null hypothesis. Otherwise we accept null hypothesis

C. The smallest value of p value  that you can use and still reject H0 is 0 .05.

perimeter of the first rectangular board is 9 feet.

step-by-step explanation:

let p = perimeter of first board.

l = length of first board

w = width of first board

length of first board = 2 * width of first board - 3

l = 2w - 3

perimeter of first board = 2l + 2w

since l = 2w-3, then

p = 2*(2w-3) + 2w which equals 4w-6 + 2w which equals 6w-6

length and width of the second board are reciprocals of corresponding length and width of the first board.

length of second board = 1/(2w-3)

width of second board = 1/w

perimeter of second board is 1/5th perimeter of the first board.

perimeter of second board = p/5

perimeter of the second board = (2/(2w-3) + 2/w)

since the perimeter of the first board is 5 times the perimeter of the second board, this means that:

6w-6 = 5*(2/(2w-3) + 2/w)

which is the same as:

6w-6 = (10/(2w-3) + 10/w)

if we multiply both sides of this equation by (2w-3), we get:

(6w-6)*(2w-3) = 10 + 10*(2w-3)/w

if we multiply both sides of this equation by w, we get:

(6w-6)*(2w-3)*w = 10*w + 10*(2w-3)

we can simplify this to become:

(6w-6)*(2w-3)*w = 10w + 20w - 30

which becomes:

(6w-6)*(2w-3)*w = 30w-30

if we divide both sides of this equation by (6w-6), we get:

(2w-3)*w = (30w-30)/(6w-6)

which becomes:

(2w-3)*w = 5

this can be simplified to:

2w^2 - 3w = 5

subtract 5 from both sides of this equation to get:

2w^2 - 3w - 5 = 0

which can be factored into:

(2w-5)*(w+1) = 0

which makes:

w = 5/2

or

w = -1.

w can't be negative so the only possible answer is w = 5/2.

if w = 5/2, then

p = 2w-3 = 5-3 = 2

we have:

p = 2

w = 5/2

p = 2l + 2w gets p = 4 + 5 = 9

the perimeter of the first board is 9 feet.

since the perimeter of the second board is 1/5 the perimeter of the first board, the perimeter of the second board is 9/5.

to see if that's correct, we substitute known values for l and w into the second board.

the length of the second board is 1/l.

this becomes 1/2.

the width of the second board is 1/w

this bgecomes 1/(5/2) = (2/5)

let l2 = length of second board.

let w2 = width of second board.

l2 = (1/2)

w2 = (2/5)

let p2= perimeter of second board.

then p2 = 9/5

since p2 = 2*l2 + 2*w2, we should get p2 = 9/5 using the dimensions of l2 and w2.

2 * l2 = 2 * (1/2) = 1

2 * w2 = 2 * (2/5) = 4/5

1 is the same as 5/5

5/5 + 4/5 = 9/5

p2 checks out good.

the dimensions as given are good.

answer to the problem is:

perimeter of the first rectangular board is 9 feet.

i can answer this question sweetie!

step-by-step explanation: