According to a certain government agency for a large country, the proportion of fatal traffic accidents in the country in which the driver had a positive blood alcohol concentration (bac) is 0.39. suppose a random sample of 105 traffic fatalities in a certain region results in 54 that involved a positive bac. does the sample evidence suggest that the region has a higher proportion of traffic fatalities involving a positive bac than the country at the alpha equals 0.1 level of significance?

The sample evidence suggest that the region has a higher proportion of traffic fatalities involving a positive BAC than the country.

Step-by-step explanation:

In this case we have to perform a hypothesis test on a proportion.

The null and alternative hypothesis are:

The level of significance is 0.1.

The standard deviation for the proportion can be calculated as:

The proportion of the sample is

The test statistic is

The one-tail P-value for z=2.421 is .

The P-value is smaller than the significance level, so the effect is significant.

The null hypothesis is rejected: the sample evidence suggest that the region has a higher proportion of traffic fatalities involving a positive BAC than the country.

the final amount you will pay is $68.04.

the tip is determined by the pre-tax amount, so we calculate the tip based on the original bill, not after we've added sales tax.

to find the tip:

we can divide 54.00 by 100 to get 1% of 54. then we multiply that by 18.

54 / 100 = .54

.54 x 18 = 9.72

tip = 9.72$

to find the tax:

we can divide 54.00 by 100 to get 1% of 54. then we can multiply that by 8 to get 8%.

54 / 100 = .54

.54 x 8 = 4.32

tax= 4.32

now we can add the tip and tax to the bill to get our total.

54 + 9.72 + 4.32 = 68.04

total: $68.04

step-by-step explanation:

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step-by-step explanation: