Given a normal distribution with image for (a)the normal -curve area to the right of x=17. (b)the normal-curve area to the left of x=22. (c)the normal-cu and image for (a)the normal -curve area to the right of x=17. (b)the normal-curve area to the left of x=22. (c)the normal-cu , find

(a)the normal -curve area to the right of x=17.
(b)the normal-curve area to the left of x=22.
(c)the normal-curve area between x=32 and x=41
(d)the value of x that has 80% of the normal-curve area to theleft.
(e)the two values of x that contain the middle 75% of thenormal-curve area

the naturalist literary movement was an extension of the realist literary movement, a movement that strove to portray life as it really was hope it

step-by-step explanation:

take it another

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)