Two swimmers start out from opposite ends of a swimming pool(red side and blue side). they cross each other for the first time at line pq, which is 21 yards from the red side and 29 yards from the blue side. they reach the opposite ends, turn around and cross again at line rs. assuming that they both travel at constant speeds, how far is line rs from the blue side? the line rs is to the right of line pq, which is 21 feet from the red side.

13 yds

Step-by-step explanation:

the blue side starter (B) swims 29yd in the time it takes the red side starter (R) to swim 21yd

their combined distance, when they meet, is 50yd (length of pool)

they pass each other and continue to the ends of the pool (combined distance, 100yd)

they swim towards each other again, and pass a second time (combined distance, 150yd)

at this point, R has swum 63yd (3*21) -- one length plus 13yd

so RS is 13yd from the blue end

you can not drow on this

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet