20 pts and a mark for right ! a chef is going to use a mixture of two brands of italian dressing. the first brand contains 9 % vinegar, and the second brand contains 13 % vinegar. the chef wants to make 200 milliliters of a dressing that is 12 % vinegar. how much of each brand should she use?

The chef needs 50 milliliters of the first brand

The chef needs 150 milliliters of the second brand

Step-by-step explanation:

A chef is going to use a mixture of two brands of Italian dressing.

Let x = the amount (in milliliter) of the first brand of Italian dressing .

Let y = the amount (in milliliter) of the second brand of Italian dressing .

The first brand contains 9 % vinegar

This means that it contains 9/100 × x

= 0.09x

The second brand contains 13 % vinegar

This means that it contains 13/100 × y

= 0.13y

The chef wants to make 200 milliliters of a dressing that is 12 % vinegar. This means that the amount of vinegar in the mixture would be

12/100 × 200 = 24

Also, the volume of first + the volume of second brand will be 200 milliliters ( volume of mixture). This means

x + y = 200 - - - - - - - -1

The combined amount of vinegar in both brands = the amount of vinegar required in the mixture. This means

0.09x + 0.13y = 24 - - - - - - - - 2

Substituting x = 200 - y into equation 2, we have

0.09(200-y) + 0.13y = 24

18 - 0.09y + 0.13y = 24

-0.09y +0.13y = 24-18

0.04y = 6

y = 6/0.04 = 150 milliliters

x = 200 - y = 200 - 150

x = 50 milliliters

answer: ouch. thats difficult

step-by-step explanation: