How many permutations of a 7-digit phone number exist

10,000,000

Step-by-step explanation:

There are 10 possible numbers for each digit (0-9).  So the number of permutations is 10^7, or 10 million.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*