Atheater has a seating capacity of 750 and charges $2 for children, $4 for students, and $6 for adults. at a certain screening with full attendance, there were half as many adults as children and students combined. the receipts totaled $3300. how many children attended the show? (let x, y, and z denote the number of children, students, and adults, respectively.)

100 children

Step-by-step explanation:

Let x, y, and z denote the number of children, students, and adults, respectively.

A theater has a seating capacity of 750

So, ---A

Theater charges $2 for children, $4 for students, and $6 for adults.

Cost for x children = 2x

Cost for y  students = 4y

Cost for y adults = 6z

The receipts totaled $3300

So, ---B

Now we are given that  there were half as many adults as children and students combined.

So, ---C

Substitute the value of x+y in A

Substitute the value of z in A and B

In A

---D

In B

---E

Solve D and E

Substitute the value of x from D in E

Substitute the value of y in D

x=100

Hence 100 children attended the show

i don't even know man. edge inuity be messing with us. i had to ask a question too.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: