Assume that you expect to hold a $20,000 investment for one year. it is forecasted to have a year end value of $21,000 with a 30% probability; a year end value of $24,000 with a 45% probability; and a year end value of $30,000 with a 25% probability. what is the standard deviation of the holding period return for this investment?

$3,762.98

Step-by-step explanation:

Let's compute first the expectancy E (the expected value) of the investment:

E = 30% of 21,000 + 45% of 24,000 + 25% of 30,000 =

0.3*21,000 + 0.45*24,000 + 0.25*30,000 = $24,600

The standard deviation s is

When replacing the expectancy in this formula, we get:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

step-by-step explanation: