Asample chosen by stratified random sampling involves a. randomly selecting one of the first k elements in an ordered population and then selecting every kth element in the population thereafter. b. a sample chosen by a knowledgeable person on the subject of the study. c. selecting a simple random sample of clusters from the available clusters in the population. d. selecting a simple random sample from each of a given number of strata formed from the elements in the population.

The answer is (d)= Selecting a simple random sample from each of a given number of strata formed from the elements in the population.

Stratified random sampling is a sampling method where the population has a number of distinct categories. The population can be organized into separate strata and each stratum is then sampled as an independent sub-population out of which individual elements can be randomly selected. In this case, each unit in a stratum, that is, each element in a group has the chance of being selected into the sample and there is adequate representation of minority sub-groups. With Stratified sampling, the best result occurs when elements within strata are internally homogeneous.

Step-by-step explanation:

step-by-step explanation:

where is the questions

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841